Add quick switcher and fix directory refresh races
- Ctrl+P quick switcher with fuzzy matching on note titles and folders; empty input lists recent notes with the previous note first; creates the note (and folders) when no note has that name; also reachable from the mobile top bar - Track recently opened notes, following renames and moves - Serialize directory refreshes and discard responses that raced with local edits; a stale response could drop an optimistically added note, and debounced callers could wait forever, leaving the workspace startup unfinished - Wait for a pending note creation before renaming it - Focus the editor after opening a note from the switcher or search
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// 快速切换的模糊匹配。目标形如"目录/标题",空白分隔的每个词都要命中;
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// 连续命中标题 > 连续命中目录 > 按顺序零散命中(如用首字母找笔记)
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export interface FuzzyMatch {
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score: number
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// 命中字符在目标中的下标,用于高亮
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positions: number[]
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}
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const BOUNDARY = new Set(['/', ' ', '-', '_', '.'])
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function isBoundary(target: string, i: number): boolean {
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return i === 0 || BOUNDARY.has(target[i - 1])
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}
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function matchTerm(term: string, target: string, lower: string, titleStart: number): FuzzyMatch | null {
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// 取最后一处连续命中:标题在末尾,优先落在标题上
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const at = lower.lastIndexOf(term)
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if (at >= 0) {
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let score = at >= titleStart ? 100 : 50
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if (at === titleStart) score += 30
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else if (isBoundary(target, at)) score += 10
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return { score, positions: Array.from(term, (_, k) => at + k) }
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}
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const positions: number[] = []
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let from = 0
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for (const ch of term) {
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const i = lower.indexOf(ch, from)
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if (i < 0) return null
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positions.push(i)
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from = i + 1
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}
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// 越分散得分越低,命中词首的字符加分
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const spread = positions[positions.length - 1] - positions[0] + 1 - positions.length
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const boundaries = positions.filter((i) => isBoundary(target, i)).length
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return { score: Math.max(1, 20 - spread + boundaries * 3), positions }
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}
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/** titleStart 为标题在 target 中的起始下标;不匹配时返回 null */
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export function fuzzyMatch(query: string, target: string, titleStart: number): FuzzyMatch | null {
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const terms = query.toLowerCase().split(/\s+/).filter(Boolean)
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if (!terms.length) return null
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const lower = target.toLowerCase()
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let score = 0
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const positions = new Set<number>()
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for (const term of terms) {
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const m = matchTerm(term, target, lower, titleStart)
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if (!m) return null
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score += m.score
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m.positions.forEach((p) => positions.add(p))
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}
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// 标题与输入完全一致时排在最前
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if (lower.slice(titleStart) === query.trim().toLowerCase()) score += 1000
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return { score, positions: [...positions].sort((a, b) => a - b) }
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}
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